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\begin{document}
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\title{\bf{Construction of Vector Valued Modular Forms of positive dimension}}
\author{Pepe Gimenez}

\date{\today}
\maketitle

\noindent
{\setlength{\baselineskip}%
{1.5\baselineskip}
\newtheorem{thm}{Theorem}
\begin{thm}Let $b_1,\ldots , b_{\mu}$ be a set of column vectors
such that $b_j \in \mathbb{C}^p$, $b_{\mu}\neq 0$, $\rho:\Gamma
\longrightarrow GL(p,\mathbb{C})$ a $p$-dimensional complex
representation , $\varepsilon$ a Multiplier System , and $r>
2\alpha$ (\ref{eq:alpha}), $r,\mu \in \mathbb{Z^+}$ then if
\begin{equation}
F(\tau)=\left(%
\begin{array}{c}
  \sum_{\nu=1}^\mu b_\nu(1)e^{2\pi i(m_1-\nu)\tau}+ \sum_{m=0}^\infty a_m(1)e^{2 \pi i(m+m_1) \tau} \\
  \vdots \\
  \sum_{\nu=1}^\mu b_\nu(p)e^{2\pi i(m_p-\nu)\tau}+ \sum_{m=0}^\infty a_m(p)e^{2 \pi i(m+m_p) \tau} \\
\end{array}%
\right),
\end{equation}
where $a_m(\nu ,r,\varepsilon)$  is a column vector in which the
$j^{th}$ component is given by
\begin{equation}
a_m(\nu ,r,\varepsilon)(j)=2 \pi \sum_{c=1}^{\infty}\frac{1}{c}
\left[ \sum_{\tiny{\begin{array}{c}
  d,c \\
  0 \leq d < c \\
  (d,c)=1 \\
\end{array}}}\varepsilon^{-1}(V_{c,d}) \left( \sum_{s=1}^p x_{js}(c,d) e^{2 \pi i m_s
\frac{d'-d}{c}}B_{c,\nu,m, \rho, \varepsilon, r}^s\right) e^{-2
\pi i \frac{dm+d'\nu}{c}} \right]
\end{equation}
where
\begin{equation}
 \rho^{-1}(V_{c,d})=\left(%
\begin{array}{ccc}
  x_{11}(c,d) & \cdots & x_{1p}(c,d) \\
  \vdots & \ddots & \vdots \\
  x_{p1}(c,d) & \cdots & x_{pp}(c,d) \\
\end{array}%
\right)
\end{equation}
where
\begin{equation}
V_{c,d}=\left(%
\begin{array}{cc}
  d' & - \frac{dd'+1}{c} \\
  c & d \\
\end{array}%
\right) \in \Gamma(1)
\end{equation}

\begin{eqnarray}\label{Eq:defBjknum}
\lefteqn{B_{c, \nu,m, \rho, \varepsilon, r}^s}\\
&&=\left( \frac{\nu -
m_s}{m+m_s}\right)^{\frac{r+1}{2}}I_{r+1}\left(\frac{4 \pi}{c}(\nu
- m_s)^{\frac{1}{2}}(m+m_s)^{\frac{1}{2}}\right)\quad if \quad
m+m_s
>
0\\
&&= \frac{2 \pi}{(r+1)!} \left(\frac{2 \pi \nu}{c} \right)^{r+1}
\quad if \quad m=m_s=0
\end{eqnarray}

\begin{equation}
a_m=\left(%
\begin{array}{c}
  \sum_{\nu=1}^\mu b_\nu (1) a_m(\nu ,r,\varepsilon)(1) \\
  \vdots \\
  \sum_{\nu=1}^\mu b_\nu (p) a_m(\nu ,r,\varepsilon)(p) \\
\end{array}%
\right)=\left(%
\begin{array}{c}
  a_m (1) \\
  \vdots \\
  a_m (p) \\
\end{array}%
\right)
\end{equation}
then
\begin{enumerate}
\item $F(\tau)$ is regular in the complex upper half-plane $
\mathcal{H}$ \item $F(\tau)$ satisfies
\begin{equation}
F(\tau)- \varepsilon^{-1}(M)(-i(c \tau +d))^r \rho^{-1} (M)
F(M\tau)= p_M(\tau)
\end{equation},
for all
\begin{equation}
M=\left(%
\begin{array}{cc}
  a & b \\
  c & d \\
\end{array}%
\right)\in \Gamma
\end{equation}

\end{enumerate}
where $p_M(\tau)$ is a column vector of polynomials on $\tau$ of
degree at most $r$.

\end{thm}
\newtheorem{lem}[thm]{Lemma}
\begin{lem}
For $r>2 \alpha$ as $m\rightarrow \infty$, we have
\begin{equation}
|a_m(\nu ,r,\varepsilon)|=O \left( (m+\kappa_m)^{-\frac{3}{4}-
\frac{r}{2}} e^{4 \pi(\nu
-\kappa_m)^{\frac{1}{2}}(m+\kappa_M)^{\frac{1}{2}}} \right)
\end{equation}
where
\begin{equation}
\kappa_m= \min{m_1,\ldots,m_p} \quad and \quad \kappa_M=
\max{m_1,\ldots,m_p}
\end{equation}
\end{lem}
\begin{proof}In \cite {[12]} Marvin Knopp proves that
given $0 \leq m_s <1$ and $q \geq 0$
\begin{equation}
c^{-q} A_{c,\nu,m_s}(m)=O \left( c^{\frac{2}{3}+ \varepsilon
}\right)
\end{equation}
where
\begin{equation}
A_{c,\nu,m_s}(m)=\sum_{\tiny{\begin{array}{c}
  d,c \\
  0 \leq d < c \\
  (d,c)=1 \\
\end{array}}} \varepsilon^{-1}(V_{c,d}) e^{2 \pi i m_s
\frac{d'-d}{c}}e^{-2 \pi i \frac{dm+d'\nu}{c}}
\end{equation}
the strategy is the same as the one in the proof of Knopp first we
can fix $s$ and show that
\begin{equation}
\begin{split}2 \pi \sum_{c=2}^{\infty}\frac{1}{c} \left[
\sum_{\tiny{\begin{array}{c}
  d,c \\
  0 \leq d < c \\
  (d,c)=1 \\
\end{array}}}\varepsilon^{-1}(V_{c,d}) \left(  x_{sj}(c,d) e^{2 \pi i m_s
\frac{d'-d}{c}} B_{c,\nu,m,  r}^s \right) e^{-2 \pi i
\frac{dm+d'\nu}{c}} \right]
 \\ \leq C(m+m_s)^{-\frac{1}{2}}e^{2 \pi
(m+m_s)^{\frac{1}{2}}(\nu-m_s)^{\frac{1}{2}}}\end{split}
\end{equation}
and show that the summations behaves as the first term as
$m\rightarrow \infty$. Here $B_{c,\nu,m, r}^s $ can be understood
as $B_{c,\nu,m, \rho, \varepsilon, r}^s$, with a MS $\varepsilon$
and a representation $\rho$ such that
\begin{equation}
\varepsilon \left(%
\begin{array}{cc}
  1 & 1 \\
  0 & 1 \\
\end{array}%
\right) \rho \left(%
\begin{array}{cc}
  1 & 1 \\
  0 & 1 \\
\end{array}%
\right)=\left(%
\begin{array}{ccccc}
  e^{2 \pi i m_1} &   & s^{th}cloumn &   &   \\
   & \ddots &  &  &  \\
  s^{th}row &  & e^{2 \pi i m_s} &  &  \\
   &  &  & \ddots &  \\
   &  &  &  & e^{2 \pi i m_p} \\
\end{array}%
\right)
\end{equation}
Also in the previous paper I showed that $|\rho(V_{c,d})|=O(c^{2
\alpha})$, which means that $|x_{ij}|=O(c^{2 \alpha})$. And since
$r> 2 \alpha$, we can write $r=q+\alpha$ where $q>0$

In the same fashion as the mentioned proof we can see that

\begin{eqnarray}
\lefteqn{2 \pi \sum_{c=2}^{\infty}\frac{1}{c}
\sum_{\tiny{\begin{array}{c}
  d,c \\
  0 \leq d < c \\
  (d,c)=1 \\
\end{array}}}\left|\varepsilon^{-1}(V_{c,d})   x_{sj}(c,d) e^{2 \pi i m_s
\frac{d'-d}{c}}B_{c,\nu,m,  r}^s  e^{-2 \pi i \frac{dm+d'\nu}{c}}
\right|
} \\
&&\leq C_1
\frac{(\nu-m_s)^{r+\frac{1}{2}}}{(m+m_s)^{\frac{1}{2}}}\sinh
\left( 2 \pi (m+m_s)^{\frac{1}{2}}(\nu-m_s)^{\frac{1}{2}}\right)
\sum_{c=2}^\infty  x_{sj}(c,d)c^{-r-2}A_{c,\nu,m_s}(m)\\
&&\leq C_2(m+m_s)^{-\frac{1}{2}}e^{2 \pi
(m+m_s)^{\frac{1}{2}}(\nu-m_s)^{\frac{1}{2}}}\sum_{c=2}^\infty
c^{-\frac{4}{3}+\varepsilon}\\
&&\leq C_3(m+m_s)^{-\frac{1}{2}}e^{2 \pi
(m+m_s)^{\frac{1}{2}}(\nu-m_s)^{\frac{1}{2}}}
\end{eqnarray}
the first term is
\begin{equation}
\begin{split}2 \pi \varepsilon^{-1}(V_{1,0})x_{1,s}(1,0) e^{2 \pi i m_s
(d'-d)}e^{-2 \pi i (dm+d'\nu)}\left( \frac{\nu -
m_s}{m+m_s}\right)^{\frac{r+1}{2}}I_{r+1}\left(4 \pi(\nu -
m_s)^{\frac{1}{2}}(m+m_s)^{\frac{1}{2}}\right)\\
=O\left((m+m_s)^{-\frac{r}{2}- \frac{3}{4}}e^{4 \pi
(m+m_s)^{\frac{1}{2}}(\nu-m_s)^{\frac{1}{2}}}\right)\end{split}
\end{equation}
therefore we can see that the series
\begin{equation}
2 \pi \sum_{c=2}^{\infty}\frac{1}{c} A_{c,\nu,m_s}(m) B_{c,\nu,m,
r}^s\
\end{equation}
converges uniformly on compacts and  absolutely. So can conclude
that
\begin{eqnarray}
a_m(\nu ,r,\varepsilon)(j)&=&2 \pi \sum_{c=1}^{\infty}\frac{1}{c}
\left[ \sum_{\tiny{\begin{array}{c}
  d,c \\
  0 \leq d < c \\
  (d,c)=1 \\
\end{array}}}\varepsilon^{-1}(V_{c,d}) \left( \sum_{s=1}^p x_{sj}(c,d) e^{2 \pi i m_s
\frac{d'-d}{c}}B_{c,\nu,m, \rho, \varepsilon, r}^s \right) e^{-2
\pi i \frac{dm+d'\nu}{c}} \right]
\\
&&\leq 2 \pi \sum_{s=1}^p\sum_{c=1}^{\infty}\frac{1}{c} \left[
\sum_{\tiny{\begin{array}{c}
  d,c \\
  0 \leq d < c \\
  (d,c)=1 \\
\end{array}}}\left|\varepsilon^{-1}(V_{c,d}) \left(  x_{sj}(c,d) e^{2 \pi i m_s
\frac{d'-d}{c}} B_{c,\nu,m, \rho, \varepsilon, r}^s\right) e^{-2
\pi i \frac{dm+d'\nu}{c}}\right| \right]
\\
&&=O \left( (m+\kappa_m)^{-\frac{3}{4}- \frac{r}{2}} e^{4 \pi(\nu
-\kappa_m)^{\frac{1}{2}}(m+\kappa_M)^{\frac{1}{2}}} \right)
\end{eqnarray}
\end{proof}
\newtheorem{cor}[thm]{Corollary}
\begin{cor}The following series converges uniformly on
$I_w=\{\tau : \mathcal{I}(\tau) > w > 0 \}$
\begin{equation}
\sum_{m=0}^\infty \left|a_m(\nu ,r,\varepsilon)(j)e^{2 \pi
i(m+m_j) \tau}\right|
\end{equation}
\end{cor}
\begin{proof}
\begin{eqnarray}
\lefteqn{\left|a_m(\nu ,r,\varepsilon)(j)e^{2 \pi i(m+m_j) \tau} \right|}\\
&& \leq C_1 \left|(m+\kappa_m)^{-\frac{3}{4}- \frac{r}{2}} e^{4
\pi(\nu -\kappa_m)^{\frac{1}{2}}(m+\kappa_M)^{\frac{1}{2}}}e^{2
\pi i(m+m_j)\tau}\right|\\
&& \leq C_2m^{-\frac{3}{4}- \frac{r}{2}}e^{-2 \pi m w+4 \pi
\mu^{\frac{1}{2}} (m+1)^{\frac{1}{2}}}\\
&&\leq C_3m^{-\frac{3}{4}} \quad \mbox{for $m$ large enough}
\end{eqnarray}
\end{proof}
\begin{proof}[Proof of the Theorem]
Let $F_\nu(\tau)$ be a column function defined in the following
way
%definincion de F_\nu
\begin{eqnarray}
\lefteqn{ F_\nu(\tau)}\\
&&=\left(%
\begin{array}{c}
  e^{2\pi i(m_1-\nu)\tau} \\
  \vdots \\
  e^{2\pi i(m_p-\nu)\tau} \\
\end{array}%
\right)+\sum_{m=0}^\infty\left(%
\begin{array}{c}
   a_m(\nu ,r,\varepsilon)(1)e^{2 \pi i(m+m_1) \tau}\\
  \vdots \\
  a_m(\nu ,r,\varepsilon)(p)e^{2 \pi i(m+m_p) \tau} \\
\end{array}%
\right)\\
%alkdjfhalskdjfhlaskdjfhkasjldfh
&&=\left(%
\begin{array}{c}
  e^{2\pi i(m_1-\nu)\tau} \\
  \vdots \\
  e^{2\pi i(m_p-\nu)\tau} \\
\end{array}%
\right)+\sum_{m=0}^\infty\left(%
\begin{array}{ccc}
  e^{2 \pi i (m+m_1)\tau} &   &   \\
    & \ddots &   \\
    &  & e^{2 \pi i (m+m_p)\tau} \\
\end{array}%
\right)\left(%
\begin{array}{c}
   a_m(\nu ,r,\varepsilon)(1)\\
  \vdots \\
  a_m(\nu ,r,\varepsilon)(p) \\
\end{array}%
\right)\\
%;adlkfj;aldkfjas;dlfkjasfd;lkj
&&=\left(%
\begin{array}{c}
  e^{2\pi i(m_1-\nu)\tau} \\
  \vdots \\
  e^{2\pi i(m_p-\nu)\tau} \\
\end{array}%
\right)+ 2 \pi \sum_{m=0}^\infty \left(%
\begin{array}{ccc}
  e^{2 \pi i (m+m_1)\tau} &   &   \\
    & \ddots &   \\
    &  & e^{2 \pi i (m+m_p)\tau} \\
\end{array}%
\right)\sum_{c=1}^{\infty}\frac{1}{c} \sum_{\tiny{\begin{array}{c}
  d,c \\
  0 \leq d < c \\
  (d,c)=1 \\
\end{array}}}\varepsilon^{-1}(V_{c,d}) \\
&&\left( \rho^{-1} (V_{c,d})\right)^t\left(%
\begin{array}{ccc}
  e^{2 \pi i m_1
\frac{d'-d}{c}} &   &   \\
    & \ddots &   \\
    &   & e^{2 \pi i m_p
\frac{d'-d}{c}} \\
\end{array}%
\right)  \left(%
\begin{array}{c}
  e^{-2 \pi i \frac{dm+d'\nu}{c}}B_{c,\nu,m, \rho,
\varepsilon, r}^1 \\
  \vdots \\
  e^{-2 \pi i \frac{dm+d'\nu}{c}}B_{c,\nu,m, \rho,
\varepsilon, r}^p  \\
\end{array}%
\right)\\
%;adlkfj;aldkfjas;dlfkjasfd;lkj
&&=\left(%
\begin{array}{c}
  e^{2\pi i(m_1-\nu)\tau} \\
  \vdots \\
  e^{2\pi i(m_p-\nu)\tau} \\
\end{array}%
\right)+ 2 \pi \sum_{m=0}^\infty \sum_{c=1}^{\infty}\frac{1}{c}
\sum_{\tiny{\begin{array}{c}
  d,c \\
  0 \leq d < c \\
  (d,c)=1 \\
\end{array}}}\varepsilon^{-1}(V_{c,d})\rho^{-1} (V_{c,d})\left(%
\begin{array}{ccc}
  e^{2 \pi i m_1
\frac{d'-d}{c}} &   &   \\
    & \ddots &   \\
    &   & e^{2 \pi i m_p
\frac{d'-d}{c}} \\
\end{array}%
\right)   \\
&& \left(%
\begin{array}{ccc}
  e^{2 \pi i (m+m_1)\tau} &   &   \\
    & \ddots &   \\
    &  & e^{2 \pi i (m+m_p)\tau} \\
\end{array}%
\right)\left(%
\begin{array}{c}
  e^{-2 \pi i \frac{dm+d'\nu}{c}}B_{c,\nu,m, \rho,
\varepsilon, r}^1 \\
  \vdots \\
  e^{-2 \pi i \frac{dm+d'\nu}{c}}B_{c,\nu,m, \rho,
\varepsilon, r}^p  \\
\end{array}%
\right)\\
%;adlkfj;aldkfjas;dlfkjasfd;lkj
&&=\left(%
\begin{array}{c}
  e^{2\pi i(m_1-\nu)\tau} \\
  \vdots \\
  e^{2\pi i(m_p-\nu)\tau} \\
\end{array}%
\right)+ 2 \pi \sum_{m=0}^\infty \sum_{c=1}^{\infty}\frac{1}{c}
\sum_{\tiny{\begin{array}{c}
  d,c \\
  0 \leq d < c \\
  (d,c)=1 \\
\end{array}}}\varepsilon^{-1}(V_{c,d})\rho^{-1} (V_{c,d}) \\
&& \left(%
\begin{array}{ccc}
  e^{2 \pi i m_1
\frac{d'-d}{c}} &   &   \\
    & \ddots &   \\
    &   & e^{2 \pi i m_p
\frac{d'-d}{c}} \\
\end{array}%
\right)  \left(%
\begin{array}{c}
  e^{-2 \pi i \frac{dm+d'\nu}{c}}B_{c,\nu,m, \rho,
\varepsilon, r}^1 e^{2 \pi i (m+m_1)\tau}\\
  \vdots \\
  e^{-2 \pi i \frac{dm+d'\nu}{c}}B_{c,\nu,m, \rho,
\varepsilon, r}^p e^{2 \pi i (m+m_p)\tau} \\
\end{array}%
\right)\\
\end{eqnarray}
By the previous corollary and lemma we have that $F(\tau)(j)$
converges absolutely on $m$ and on $c$, and therefore  the above
interchanges are justified. Also we can see that $F(\tau)$ can be
written in the following form
\begin{equation}
F(\tau)=\left(%
\begin{array}{c}
  \sum_{\nu=1}^\mu b_\nu(1)F_\nu(\tau)(1) \\
  \vdots \\
  \sum_{\nu=1}^\mu b_\nu(p)F_\nu(\tau)(p) \\
\end{array}%
\right)
\end{equation}
also since the series converges, $F(\tau)$ is regular in
$\mathcal{H}$. We will prove the result for $\tau=iy$ and $y>0$,
and by analytic continuation the result will follow for $\tau$ on
$\mathcal{H}$.

Now let us rewrite the function $F_\nu(\tau)(j)$ in the following
manner
\begin{eqnarray*}
\lefteqn{F_\nu(\tau)(j) - e^{2\pi i(m_j-\nu)\tau}}\\
&&= 2 \pi \sum_{m=0}^\infty \sum_{c=1}^{\infty}\frac{1}{c}
\sum_{\tiny{\begin{array}{c}
  d,c \\
  0 \leq d < c \\
  (d,c)=1 \\
\end{array}}}\varepsilon^{-1}(V_{c,d})  \left( \sum_{s=1}^p x_{js}(c,d) e^{2 \pi i m_s
\frac{d'-d}{c}}\right) \\
&& \quad \quad e^{-2 \pi i \frac{dm+d'\nu}{c}}B_{c,\nu,m, \rho,
\varepsilon, r}^s e^{2\pi i(m+m_s)\tau}\\
&&=2 \pi \sum_{m=0}^\infty
\sum_{s=1}^p\sum_{c=1}^{\infty}\frac{1}{c}
\sum_{\tiny{\begin{array}{c}
  d,c \\
  0 \leq d < c \\
  (d,c)=1 \\
\end{array}}}\varepsilon^{-1}(V_{c,d})    x_{js}(c,d) e^{2 \pi i
\frac {d'(m_s-\nu)}{c}} \\
&& \quad \quad B_{c,\nu,m, \rho, \varepsilon, r}^s e^{2\pi
i(m+m_s)(\tau - \frac{d}{c})}
\end{eqnarray*}
to continue with the proof we will need the Lipschitz summation
formula for $p>-1$, $0 \leq m_s<1$ and $\mathcal{R}(t)>0$
\begin{eqnarray}
\lefteqn{\sum_{n=0}^{\infty}(n+m_s)^p e^{2 \pi it(n+m_s)}}\\
&&=\frac{\Gamma(p+1)}{(2 \pi)^{p+1}}\sum_{q=- \infty}^{\infty}e^{2
\pi i m_s}(t-q i)^{-p-1}, \quad \mbox{ if } m_s +p>0\\
&&=-\frac{1}{2} + \frac{1}{2 \pi}\lim_{N \rightarrow \infty}
\sum_{q=-N}{N}(t+q i)^{-1}, \quad \mbox{ if } m_s =p=0
\end{eqnarray}
\begin{lem}If  $m_s>0$ we have
\begin{equation}
\sum_{m=0}^\infty B_{c,\nu,m, \rho, \varepsilon, r}^s e^{2\pi
i(m+m_s)(\tau - \frac{d}{c})}= \sum_{q=-\infty}^\infty e^{2\pi i
m_s q}\left(-i(c\tau + d -cq) \right)^r \sum_{p=r+1}^\infty
\frac{1}{p!} \left(\frac{2 \pi i (\nu -m_s)}{c^2 \tau +c d -cq}
\right)^p
\end{equation}
and if $m_s=0$ we have
\begin{equation}\begin{split}
\sum_{m=0}^\infty B_{c,\nu,m, \rho, \varepsilon, r}^se^{2\pi
i(m+m_s)(\tau - \frac{d}{c})}= \frac{1}{2} \left( \frac{2 \pi
\nu}{c}\right)^{r+1} \frac{1}{(r+1)!} + \\
\lim_{N\rightarrow \infty} \sum_{q=-N}^N \left(-i(c\tau + d -cq)
\right)^r \sum_{p=r+1}^\infty \frac{1}{p!} \left(\frac{2 \pi i \nu
}{c^2 \tau +c d -cq} \right)^p
\end{split}
\end{equation}
\end{lem}
\begin{proof}It is a simply application of the Lipschitz formula
and the power series expression for $I_{r+1}$, in the same way
done by Knopp in [1].
\end{proof}
The above result implies that
% aqui va la nueva definicion de F_v
\begin{eqnarray}
\lefteqn{F_\nu(\tau)}\\
&&=\left(%
\begin{array}{c}
  e^{2\pi i(m_1-\nu)\tau} \\
  \vdots \\
  e^{2\pi i(m_p-\nu)\tau} \\
\end{array}%
\right)+K +\sum_{c=1}^{\infty} \sum_{\tiny{\begin{array}{c}
  d,c \\
  0 \leq d < c \\
  (d,c)=1 \\
\end{array}}}\varepsilon^{-1}(V_{c,d}) \rho^{-1}(V_{c,d})\\
&&\left(%
\begin{array}{c}
  e^{2 \pi i
\frac {d'(m_1-\nu)}{c}}\lim_{N\rightarrow \infty} \sum_{q=-N}^N
e^{2\pi i m_1 q}\left(-i(c\tau + d -cq) \right)^r
\sum_{p=r+1}^\infty \frac{1}{p!} \left(\frac{2 \pi i (\nu
-m_1)}{c^2 \tau +c d -cq}
\right)^p\\
  \vdots \\
  e^{2 \pi i
\frac {d'(m_p-\nu)}{c}}\lim_{N\rightarrow \infty} \sum_{q=-N}^N
e^{2\pi i m_p q}\left(-i(c\tau + d -cq) \right)^r
\sum_{p=r+1}^\infty \frac{1}{p!} \left(\frac{2 \pi i (\nu
-m_p)}{c^2 \tau +c d -cq}
\right)^p \\
\end{array}%
\right)
\end{eqnarray}
where $K$ is a column vector independent of $\tau$  given by
\begin{equation}
K=\frac{1}{2}\sum_{c=1}^{\infty} \sum_{\tiny{\begin{array}{c}
  d,c \\
  0 \leq d < c \\
  (d,c)=1 \\
\end{array}}}\varepsilon^{-1}(V_{c,d}) \rho^{-1}(V_{c,d})\left(%
\begin{array}{c}
  e^{2 \pi i
\frac {d'(m_1-\nu)}{c}}\varphi(1) \\
  \vdots \\
  e^{2 \pi i
\frac {d'(m_p-\nu)}{c}}\varphi(p) \\
\end{array}%
\right)
\end{equation}
where
\begin{eqnarray}
\varphi(j)&=&\left(\frac{2 \pi \nu}{c}
\right)^{r+1}\frac{1}{(r+1)!} \quad \mbox{ if } m_j=0\\
&=& 0\quad \mbox{ if } m_j>0
\end{eqnarray}
Now let $G_\nu(\tau)=F_\nu(\tau)-K$ then

\begin{eqnarray}
G_\nu(\tau)(j)&=&e^{2\pi i(m_j-\nu)\tau}+\sum_{c=1}^{\infty}
\sum_{\tiny{\begin{array}{c}
  d,c \\
  0 \leq d < c \\
  (d,c)=1 \\
\end{array}}}\varepsilon^{-1}(V_{c,d})\sum_{s=1}^p x_{js}(c,d)e^{2 \pi i
\frac {d'(m_s-\nu)}{c}}\\
&&\lim_{N\rightarrow \infty} \sum_{q=-N}^N e^{2\pi i m_s
q}\left(-i(c\tau + d -cq) \right)^r \sum_{p=r+1}^\infty
\frac{1}{p!} \left(\frac{2 \pi i (\nu -m_s)}{c^2 \tau +c d -cq}
\right)^p
\end{eqnarray}



now let $\delta = d-cq$, as $q$ runs through all integers and as
$d$ runs through the set
\begin{equation}
D_c= \left\{ d | \exists \left(%
\begin{array}{cc}
  * & * \\
  c & d \\
\end{array}%
\right) \in \Gamma(1)  \mbox{, with } 0 \leq  -d < c \right\}
\end{equation}
$\delta$ assumes exactly once, each value $\delta \in D^c= \{
\delta \in \mathbb{Z} | (c,\delta)=1\}$, and we can define
$V_{c,\delta}=S^{-q}V_{c,d}$, we have
\begin{eqnarray}
\lefteqn{\varepsilon^{-1}(V{c,d})\rho^{-1}(V_{c,d})}\\
&&=\varepsilon^{-1}(V{c,d}) \left(%
\begin{array}{ccc}
  x_{11}(c,d) & \cdots & x_{1p}(c,d) \\
  \vdots & \ddots & \vdots \\
  x_{p1}(c,d) & \cdots & x_{pp}(c,d) \\
\end{array}%
\right)\\
&&=\varepsilon^{-1}(V_{c,\delta}S^q) \rho^{-1}(V_{c,\delta}S^q)\\
&&=\varepsilon^{-1}(V_{c,\delta}) \left(%
\begin{array}{ccc}
  e^{-2 \pi i m_1 q} &   &   \\
    & \ddots &   \\
    &   & e^{-2 \pi i m_p q} \\
\end{array}%
\right)\rho^{-1}(V_{c,\delta})\\
&&=\varepsilon^{-1}(V_{c,\delta}) \left(%
\begin{array}{ccc}
  e^{-2 \pi i m_1 q} &   &   \\
    & \ddots &   \\
    &   & e^{-2 \pi i m_p q} \\
\end{array}%
\right)\left(%
\begin{array}{ccc}
  x_{11}(c,\delta) & \cdots & x_{1p}(c,\delta) \\
  \vdots & \ddots & \vdots \\
  x_{p1}(c,\delta) & \cdots & x_{pp}(c,\delta) \\
\end{array}%
\right)
\end{eqnarray}
and therefore
\begin{equation}
\varepsilon^{-1}(V_{c,d})x_{js}(c,d)=
\varepsilon^{-1}(V_{c,\delta})e^{-2 \pi i m_s q}x_{js}(c,\delta)
\end{equation}
Note also that  $\delta'=d'$, and then we have
\begin{equation}
e^{-\frac {2 \pi i \delta ' (\nu-m_s)}{c}}=e^{-\frac {2 \pi i d'
(\nu-m_s)}{c}}
\end{equation}
now we can rewrite $G_{\nu}(\tau)(j)$, but instead of writing
$\delta$ we write $d$
\begin{eqnarray*}
\lefteqn{G_{\nu}(\tau)(j)}\\
&&= e^{2\pi i(m_j-\nu)\tau}+\sum_{s=1}^p\sum_{c=1}^{\infty}
\lim_{N\rightarrow \infty} \sum_{\tiny{\begin{array}{c}
  d=-N \\
   d \in D^c \\
\end{array}}}^N\varepsilon^{-1}(V_{c,d})
x_{js}(c,d) e^{2 \pi i
\frac {d'(m_s-\nu)}{c}}\\
&&\quad \quad \left(-i(c\tau + d ) \right)^r \sum_{p=r+1}^\infty
\frac{1}{p!}
\left(\frac{2 \pi i (\nu -m_s) }{c(c \tau + d )} \right)^p\\
%alkjdsfhhlakjdfhalsdfjh
&&= e^{2\pi i(m_j-\nu)\tau}+\sum_{s=1}^p\sum_{c=1}^{\infty}
\lim_{N\rightarrow \infty} \sum_{\tiny{\begin{array}{c}
  d=-N \\
   d \in D^c \\
\end{array}}}^N\varepsilon^{-1}(V_{c,d})
x_{js}(c,d) e^{2 \pi i
\frac {d'(m_s-\nu)}{c}}\\
&&\quad \quad \left(-i(c\tau + d ) \right)^r \frac{1}{(r+1)!}
\left(\frac{2 \pi i (\nu -m_s) }{c(c \tau + d )} \right)^{r+1}\\
%lasfdsahdfhjhfhf
&&\quad \quad + \sum_{s=1}^p\sum_{c=1}^{\infty} \lim_{N\rightarrow
\infty} \sum_{\tiny{\begin{array}{c}
  d=-N \\
   d \in D^c \\
\end{array}}}^N\varepsilon^{-1}(V_{c,d})
x_{js}(c,d) e^{2 \pi i
\frac {d'(m_s-\nu)}{c}}\\
&&\quad \quad \left(-i(c\tau + d ) \right)^r \sum_{p=r+2}^\infty
\frac{1}{p!} \left(\frac{2 \pi i (\nu -m_s) }{c(c \tau + d )}
\right)^p
\end{eqnarray*}
The separation into two sums is justified since the first
converges by Lemma (2.10) in [1], which is applicable since
$\tau=iy$ with $y>0$, and the second is absolutely convergent
triple sum, which can be proven by using Lemma (2.5) in [1], and
therefore the second sum can be rearranged in any manner.

Now let
\begin{equation}
V=\left(%
\begin{array}{cc}
  \alpha & \beta \\
  \gamma & \delta \\
\end{array}%
\right) \in \Gamma(1), \quad \alpha >0, \quad \beta<0 \quad \delta
> \gamma >0
\end{equation}
and $t=(\gamma - \frac{\beta}{2})\delta^{-1}$, and define
$\mathcal{J}_V(K)$ to be the trapezoid in the c-d plane bounded by
the lines
\begin{equation}
c=0, \quad \alpha c + \gamma d=tK, \quad \delta d + \beta c= \pm K
\end{equation}
we obtain
\begin{eqnarray*}
\lefteqn{G_{\nu}(\tau)(j)}\\
%alkjdsfhhlakjdfhalsdfjh
&&= e^{2\pi i(m_j-\nu)\tau}+\sum_{s=1}^p\lim_{K\rightarrow
\infty}\sum_{c=1}^{\infty} \sum_{\tiny{\begin{array}{c}
  (c,d) \in \mathcal{J}_V(K) \\
   d \in D^c \\
\end{array}}}\varepsilon^{-1}(V_{c,d})
x_{js}(c,d) e^{2 \pi i
\frac {d'(m_s-\nu)}{c}}\\
&&\quad \quad \left(-i(c\tau + d ) \right)^r \frac{1}{(r+1)!}
\left(\frac{2 \pi i (\nu -m_s) }{c(c \tau + d )} \right)^{r+1}\\
%lasfdsahdfhjhfhf
&&\quad \quad + \sum_{s=1}^p\lim_{K\rightarrow
\infty}\sum_{c=1}^{\infty} \sum_{\tiny{\begin{array}{c}
  (c,d) \in \mathcal{J}_V(K) \\
   d \in D^c \\
\end{array}}}\varepsilon^{-1}(V_{c,d})
x_{js}(c,d) e^{2 \pi i
\frac {d'(m_s-\nu)}{c}}\\
&&\quad \quad \left(-i(c\tau + d ) \right)^r \sum_{p=r+2}^\infty
\frac{1}{p!} \left(\frac{2 \pi i (\nu -m_s) }{c(c \tau + d )}
\right)^p\\
%aladjkdfsalkjhadfskjlfdsaheasf
&& =e^{2\pi i(m_j-\nu)\tau}+\sum_{s=1}^p\lim_{K\rightarrow
\infty}\sum_{c=1}^{\infty} \sum_{\tiny{\begin{array}{c}
  (c,d) \in \mathcal{J}_V(K) \\
   d \in D^c \\
\end{array}}}\varepsilon^{-1}(V_{c,d})
x_{js}(c,d) e^{2 \pi i
\frac {d'(m_s-\nu)}{c}}\\
&&\quad \quad \left(-i(c\tau + d ) \right)^r \left(e^{\frac{2 \pi
i (\nu -m_s) }{c(c \tau + d )}}-\sum_{p=0}^r \frac{1}{p!}
\left(\frac{2 \pi i (\nu -m_s) }{c(c \tau + d )} \right)^p \right)
\end{eqnarray*}
Now let
\begin{eqnarray}
\lefteqn{S_{\nu,K}(\tau)}\\
&& =\left(%
\begin{array}{c}
  e^{2\pi i(m_1-\nu)\tau} \\
  \vdots \\
  e^{2\pi i(m_p-\nu)\tau} \\
\end{array}%
\right)+\sum_{c=1}^{\infty} \sum_{\tiny{\begin{array}{c}
  (c,d) \in \mathcal{J}_V(K) \\
   d \in D^c \\
\end{array}}}\varepsilon^{-1}(V_{c,d})\rho^{-1}(V_{c,d})\left(-i(c\tau + d )
\right)^r\\
&&
 \left(%
\begin{array}{c}
  e^{2 \pi i
\frac {d'(m_1-\nu)}{c}}e^{\frac{2 \pi i (\nu -m_1) }{c(c \tau + d )}} \\
  \vdots \\
  e^{2 \pi i
\frac {d'(m_p-\nu)}{c}} e^{\frac{2 \pi i (\nu -m_p) }{c(c \tau + d )}}\\
\end{array}%
\right)
\end{eqnarray}
and since $V_{c,d} \in SL(2,\mathbb{Z})$ we can see that
\begin{equation}
e^{2 \pi i \frac {d'(m_s-\nu)}{c}}e^{\frac{2 \pi i (\nu -m_s)
}{c(c \tau + d )}}=e^{2 \pi i (m_s- \nu)V_{c,d}\tau}
\end{equation}
and therefore
\begin{eqnarray}
\lefteqn{S_{\nu,K}(\tau)}\\
&& =\left(%
\begin{array}{c}
  e^{2\pi i(m_1-\nu)\tau} \\
  \vdots \\
  e^{2\pi i(m_p-\nu)\tau} \\
\end{array}%
\right)+\sum_{c=1}^{\infty} \sum_{\tiny{\begin{array}{c}
  (c,d) \in \mathcal{J}_V(K) \\
   d \in D^c \\
\end{array}}}\varepsilon^{-1}(V_{c,d})\rho^{-1}(V_{c,d})\left(-i(c\tau + d )
\right)^r\\
&&
 \left(%
\begin{array}{c}
  e^{2 \pi i (m_1- \nu)V_{c,d}\tau} \\
  \vdots \\
  e^{2 \pi i (m_p- \nu)V_{c,d}\tau}\\
\end{array}%
\right)
\end{eqnarray}
now we can include the first term in the summation, since
$\varepsilon(I)\rho(I)(-i)^{-r}=I$ and we have that
\begin{equation}
\left(%
\begin{array}{c}
  e^{2\pi i(m_1-\nu)\tau} \\
  \vdots \\
  e^{2\pi i(m_p-\nu)\tau} \\
\end{array}%
\right)=\varepsilon^{-1}(I)\rho^{-1}(I)(-i)^r\left(%
\begin{array}{c}
  e^{2 \pi i (m_1- \nu)I\tau} \\
  \vdots \\
  e^{2 \pi i (m_p- \nu)I\tau} \\
\end{array}%
\right)
\end{equation}
now we can include the pair $(c,d)=(0,1)$ and therefore we get
\begin{eqnarray}
S_{\nu,K}(\tau)&=&\sum_{c=0}^{\infty} \sum_{\tiny{\begin{array}{c}
  (c,d) \in \mathcal{J}_V(K) \\
   d \in D^c \\
   (c,d)\neq (0,-1)\\
\end{array}}}\varepsilon^{-1}(V_{c,d})\rho^{-1}(V_{c,d})\left(-i(c\tau + d )
\right)^r\\
&&
 \left(%
\begin{array}{c}
  e^{2 \pi i (m_1- \nu)V_{c,d}\tau} \\
  \vdots \\
  e^{2 \pi i (m_p- \nu)V_{c,d}\tau}\\
\end{array}%
\right)
\end{eqnarray}
we can now extend the region $\mathcal{J}_V(K)$ to
$\mathcal{P}_V(K)$, consisting in reflecting $\mathcal{J}_V(K)$
through the origin by including with $V_{c,d}$ and $-V_{c,d}$, and
since we have that
\begin{equation}
\varepsilon^{-1}(V_{c,d})\rho^{-1}(V_{c,d})\left(-i(c\tau + d )
\right)^r
=\varepsilon^{-1}(-V_{c,d})\rho^{-1}(-V_{c,d})\left(-i(-c\tau - d
) \right)^r
\end{equation}
and
\begin{equation}
e^{2 \pi i (m_j- \nu)V_{c,d}\tau}=e^{2 \pi i (m_j-
\nu)-V_{c,d}\tau}
\end{equation}
we see that if we make the summation over $\mathcal{P}_V(K)$,
every term of $S_{\nu,K}(\tau)$ occurs twice and therefore
\begin{eqnarray}
 S_{\nu,K} (\tau)&=&\frac{1}{2}\sum_{c \in \mathbb{Z}}
 \sum_{\tiny{\begin{array}{c}
  (c,d) \in \mathcal{P}_V(K) \\
   d \in D^c \\
\end{array}}}\varepsilon^{-1}(V_{c,d})\rho^{-1}(V_{c,d})\left(-i(c\tau + d )
\right)^r\\
&&
 \left(%
\begin{array}{c}
  e^{2 \pi i (m_1- \nu)V_{c,d}\tau} \\
  \vdots \\
  e^{2 \pi i (m_p- \nu)V_{c,d}\tau}\\
\end{array}%
\right)
\end{eqnarray}
now $\mathcal{P}_V(K)$ is bounded by
\begin{equation}
\alpha c + \gamma d=\pm tK, \quad \delta d + \beta c= \pm K
\end{equation}
Therefore we get
\begin{eqnarray}
\lefteqn{\varepsilon^{-1}(V) \rho^{-1}(V) \left(-i(\gamma \tau +
\delta ) \right)^r S_{\nu,K}(V\tau)}\\
&&=\frac{1}{2}\sum_{c \in \mathbb{Z}} \sum_{\tiny{\begin{array}{c}
  (c,d) \in \mathcal{P}_V(K) \\
   d \in D^c \\
\end{array}}}\varepsilon^{-1}(V)\varepsilon^{-1}(V_{c,d})\rho^{-1}(V)\rho^{-1}(V_{c,d})\\
&&\left(-i(\gamma \tau + \delta ) \right)^r \left(-i(cV\tau + d )
\right)^r
 \left(%
\begin{array}{c}
  e^{2 \pi i (m_1- \nu)V_{c,d}V\tau} \\
  \vdots \\
  e^{2 \pi i (m_p- \nu)V_{c,d}V\tau}\\
\end{array}%
\right)\\
%alkjdsfhlasdkjfhlasdjkfhlakjdsfh
&&=\frac{1}{2}\sum_{c \in \mathbb{Z}} \sum_{\tiny{\begin{array}{c}
  (c,d) \in \mathcal{P}_V(K) \\
   d \in D^c \\
\end{array}}}\varepsilon^{-1}(V_{c,d}V)\rho^{-1}(V_{c,d}V)\\
&& \left(-i((\alpha c+\gamma d)\tau + (\beta c +\delta d )
\right)^r
 \left(%
\begin{array}{c}
  e^{2 \pi i (m_1- \nu)V_{c,d}V\tau} \\
  \vdots \\
  e^{2 \pi i (m_p- \nu)V_{c,d}V\tau}\\
\end{array}%
\right)
\end{eqnarray}
now we can make the transformation $c'=\alpha c+\gamma d$ and
$d'=\beta c +\delta d $ which is a 1-1 transformation from
$\mathcal{P}_V(K)$ to the rectangle
\begin{equation}
|c'|\leq tK, \quad \quad |d'| \leq K
\end{equation}
also this map is a 1-1 correspondence between the pairs $\{(c,d) |
c \in \mathbb{Z}, d \in D^c\}$ and the pairs $\{(c',d') | c' \in
\mathbb{Z}, d' \in D^{c'}\}$, and then
\begin{eqnarray}
\lefteqn{\varepsilon^{-1}(V) \rho^{-1}(V) \left(-i(\gamma \tau +
\delta ) \right)^r S_{\nu,K}(V\tau)}\\
&&=\frac{1}{2}\sum_{\tiny{\begin{array}{c}
  c' \in \mathbb{Z} \\
   |c'|\leq tK \\
\end{array}}} \sum_{\tiny{\begin{array}{c}
  d' \in D^c \\
    |d'| \leq K\\
\end{array}}}\varepsilon^{-1}(V_{c',d'})\rho^{-1}(V_{c',d'})\\
&& \left(-i(c'\tau + d' ) \right)^r
 \left(%
\begin{array}{c}
  e^{2 \pi i (m_1- \nu)V_{c',d'}\tau} \\
  \vdots \\
  e^{2 \pi i (m_p- \nu)V_{c',d'}\tau}\\
\end{array}%
\right)\\
%alkjdsfhlasdkjfhlasdjkfhlakjdsfh
&&=\left(%
\begin{array}{c}
  e^{2 \pi i (m_1- \nu)\tau} \\
  \vdots \\
  e^{2 \pi i (m_p- \nu)\tau}\\
\end{array}%
\right) + \sum_{\tiny{\begin{array}{c}
  c \in \mathbb{Z} \\
   0< c\leq tK \\
\end{array}}} \sum_{\tiny{\begin{array}{c}
  d \in D^c \\
    |d| \leq K\\
\end{array}}}\varepsilon^{-1}(V_{c,d})\rho^{-1}(V_{c,d})\\
&& \left(-i(c\tau + d ) \right)^r
 \left(%
\begin{array}{c}
  e^{2 \pi i (m_1- \nu)V_{c,d}\tau} \\
  \vdots \\
  e^{2 \pi i (m_p- \nu)V_{c,d}\tau}\\
\end{array}%
\right)
\end{eqnarray}
now
\begin{eqnarray}
\lefteqn{\varepsilon^{-1}(V) \rho^{-1}(V) \left(-i(\gamma \tau +
\delta ) \right)^r G_{\nu}(V\tau)}\\
&&=\lim_{k\rightarrow \infty} (\varepsilon^{-1}(V) \rho^{-1}(V)
\left(-i(\gamma \tau + \delta ) \right)^r S_{\nu,K}(V\tau)\\
&&- \sum_{c=1}^{\infty} \sum_{\tiny{\begin{array}{c}
  (c,d) \in \mathcal{J}_V(K) \\
   d \in D^c \\
\end{array}}}\varepsilon^{-1}(V)\varepsilon^{-1}(V_{c,d})\rho^{-1}(V)\rho^{-1}(V_{c,d})\left(-i(\gamma \tau + \delta ) \right)^r\\
&& \left(-i(cV\tau + d ) \right)^r
 \left(%
\begin{array}{c}
  e^{2 \pi i
\frac {d'(m_1-\nu)}{c}}\sum_{p=0}^r \frac{1}{p!}
\left(\frac{2 \pi i (\nu -m_1) }{c(c V\tau + d )} \right)^p  \\
  \vdots \\
  e^{2 \pi i
\frac {d'(m_p-\nu)}{c}} \sum_{p=0}^r \frac{1}{p!}
\left(\frac{2 \pi i (\nu -m_p) }{c(c V\tau + d )} \right)^p \\
\end{array}%
\right))\\
&&=\left(%
\begin{array}{c}
  e^{2 \pi i (m_1- \nu)\tau} \\
  \vdots \\
  e^{2 \pi i (m_p- \nu)\tau}\\
\end{array}%
\right) +\lim_{k\rightarrow \infty} (\sum_{\tiny{\begin{array}{c}
  c \in \mathbb{Z} \\
   0< c\leq tK \\
\end{array}}} \sum_{\tiny{\begin{array}{c}
  d \in D^c \\
    |d| \leq K\\
\end{array}}}\varepsilon^{-1}(V_{c,d})\rho^{-1}(V_{c,d})\left(-i(c\tau + d ) \right)^r
 \left(%
\begin{array}{c}
  e^{2 \pi i (m_1- \nu)V_{c,d}\tau} \\
  \vdots \\
  e^{2 \pi i (m_p- \nu)V_{c,d}\tau}\\
\end{array}%
\right)\\
&& - \sum_{c=1}^{\infty} \sum_{\tiny{\begin{array}{c}
  (c,d) \in \mathcal{J}_V(K) \\
   d \in D^c \\
\end{array}}}\varepsilon^{-1}(V_{c,d}V)\rho^{-1}(V_{c,d}V)\left(-i(\gamma \tau + \delta ) \right)^r \left(-i(cV\tau + d )
\right)^r\\
&&
 \left(%
\begin{array}{c}
  e^{2 \pi i
\frac {d'(m_1-\nu)}{c}}\sum_{p=0}^r \frac{1}{p!}
\left(\frac{2 \pi i (\nu -m_1) }{c(c V\tau + d )} \right)^p  \\
  \vdots \\
  e^{2 \pi i
\frac {d'(m_p-\nu)}{c}} \sum_{p=0}^r \frac{1}{p!}
\left(\frac{2 \pi i (\nu -m_p) }{c(c V\tau + d )} \right)^p \\
\end{array}%
\right))
\end{eqnarray}
also using lemma (2.13) in [1].
\begin{eqnarray}
\lefteqn{ G_{\nu}(\tau)}\\
&&=\left(%
\begin{array}{c}
  e^{2 \pi i (m_1- \nu)\tau} \\
  \vdots \\
  e^{2 \pi i (m_p- \nu)\tau}\\
\end{array}%
\right) +\lim_{k\rightarrow \infty} (\sum_{\tiny{\begin{array}{c}
  c \in \mathbb{Z} \\
   0< c\leq tK \\
\end{array}}} \sum_{\tiny{\begin{array}{c}
  d \in D^c \\
    |d| \leq K\\
\end{array}}}\varepsilon^{-1}(V_{c,d})\rho^{-1}(V_{c,d})\left(-i(c\tau + d ) \right)^r
 \left(%
\begin{array}{c}
  e^{2 \pi i (m_1- \nu)V_{c,d}\tau} \\
  \vdots \\
  e^{2 \pi i (m_p- \nu)V_{c,d}\tau}\\
\end{array}%
\right)\\
&& - \sum_{\tiny{\begin{array}{c}
  c \in \mathbb{Z} \\
   0< c\leq tK \\
\end{array}}} \sum_{\tiny{\begin{array}{c}
  d \in D^c \\
    |d| \leq K\\
\end{array}}}\varepsilon^{-1}(V_{c,d})\rho^{-1}(V_{c,d}) \left(-i(c\tau + d )
\right)^r
 \left(%
\begin{array}{c}
  e^{2 \pi i
\frac {d'(m_1-\nu)}{c}}\sum_{p=0}^r \frac{1}{p!}
\left(\frac{2 \pi i (\nu -m_1) }{c(c \tau + d )} \right)^p  \\
  \vdots \\
  e^{2 \pi i
\frac {d'(m_p-\nu)}{c}} \sum_{p=0}^r \frac{1}{p!}
\left(\frac{2 \pi i (\nu -m_p) }{c(c \tau + d )} \right)^p \\
\end{array}%
\right))
\end{eqnarray}
therefore

\begin{eqnarray}
\lefteqn{ G_{\nu}(\tau)-\varepsilon^{-1}(V) \rho^{-1}(V)
\left(-i(\gamma \tau + \delta ) \right)^r G_{\nu}(V\tau)}\\
&&=\lim_{k\rightarrow \infty} (\sum_{c=1}^{\infty}
\sum_{\tiny{\begin{array}{c}
  (c,d) \in \mathcal{J}_V(K) \\
   d \in D^c \\
\end{array}}}\varepsilon^{-1}(V_{c,d}V)\rho^{-1}(V_{c,d}V)\left(-i(\gamma \tau + \delta ) \right)^r \left(-i(cV\tau + d )
\right)^r\\
&&
 \left(%
\begin{array}{c}
  e^{2 \pi i
\frac {d'(m_1-\nu)}{c}}\sum_{p=0}^r \frac{1}{p!}
\left(\frac{2 \pi i (\nu -m_1) }{c(c V\tau + d )} \right)^p  \\
  \vdots \\
  e^{2 \pi i
\frac {d'(m_p-\nu)}{c}} \sum_{p=0}^r \frac{1}{p!}
\left(\frac{2 \pi i (\nu -m_p) }{c(c V\tau + d )} \right)^p \\
\end{array}%
\right)\\
 && - \sum_{\tiny{\begin{array}{c}
  c \in \mathbb{Z} \\
   0< c\leq tK \\
\end{array}}} \sum_{\tiny{\begin{array}{c}
  d \in D^c \\
    |d| \leq K\\
\end{array}}}\varepsilon^{-1}(V_{c,d})\rho^{-1}(V_{c,d}) \left(-i(c\tau + d )
\right)^r
 \left(%
\begin{array}{c}
  e^{2 \pi i
\frac {d'(m_1-\nu)}{c}}\sum_{p=0}^r \frac{1}{p!}
\left(\frac{2 \pi i (\nu -m_1) }{c(c \tau + d )} \right)^p  \\
  \vdots \\
  e^{2 \pi i
\frac {d'(m_p-\nu)}{c}} \sum_{p=0}^r \frac{1}{p!}
\left(\frac{2 \pi i (\nu -m_p) }{c(c \tau + d )} \right)^p \\
\end{array}%
\right))
\end{eqnarray}
now since the factor$(\gamma \tau + \delta )^r$ combine with $(c
V\tau + d )^{r-p}$ produces a polynomial of degree at most $r$. On
the other hand the limit of a sequence of polynomials of degree at
most $r$ converging at $r+1$ points is a polynomial of degree at
most $r$.

Now since $F_\nu(\tau) = G_\nu(\tau)+K$, then we have that
$F_\nu(V\tau) = G_\nu(V\tau)+K$, therefore we have that
\begin{equation}
F_{\nu}(\tau)-\varepsilon^{-1}(V) \rho^{-1}(V) \left(-i(\gamma
\tau + \delta ) \right)^r F_{\nu}(V\tau)=p_{V,\nu}(\tau, r,
\varepsilon, \rho)
\end{equation}
for
\begin{equation}
V=\left(%
\begin{array}{cc}
  \alpha & \beta \\
  \gamma & \delta \\
\end{array}%
\right) \in \Gamma(1), \quad \alpha >0, \quad \beta<0 \quad \delta
> \gamma >0
\end{equation}
to prove it for every $M=\left(%
\begin{array}{cc}
  a & b \\
  c & d \\
\end{array}%
\right) \in \Gamma(1)$, first we see that if $M=S^q$, we have
\begin{equation}
F_\nu(S^q \tau) =\left(%
\begin{array}{ccc}
  e^{2 \pi i q m_1} &   &   \\
   & \ddots &   \\
    &   & e^{2 \pi i q m_p} \\
\end{array}%
\right)F_\nu(\tau)
\end{equation}
which follows from the fourier expansion of $F_\nu(\tau)$,
otherwise it is easy to show that exist $m,n \in \mathbb{Z}$ and
$V=\left(%
\begin{array}{cc}
  \alpha & \beta \\
  \gamma & \delta \\
\end{array}%
\right) \in \Gamma(1)$ such that
\begin{equation}
M=S^kVS^n,  \quad \alpha >0, \quad \beta<0 \quad \delta
> \gamma >0 \quad \gamma=c,\quad \delta= d-cn
\end{equation}
and therefore
\begin{eqnarray}
F_\nu(M\tau)&=& F_\nu(S^kVS^n\tau)=\left(%
\begin{array}{ccc}
  e^{2 \pi i k m_1} &   &   \\
   & \ddots &   \\
    &   & e^{2 \pi i k m_p} \\
\end{array}%
\right)F_\nu(VS^n\tau)\\
&&=\left(%
\begin{array}{ccc}
  e^{2 \pi i k m_1} &   &   \\
   & \ddots &   \\
    &   & e^{2 \pi i k m_p} \\
\end{array}%
\right)\varepsilon(V)\rho(V)\left(-i(\gamma S^n\tau + \delta )
\right)^r\\
&&\left(F_\nu(S^n\tau)-p_{V,\nu}(S^n\tau,\varepsilon,\rho)\right)
\end{eqnarray}
and since $\left(-i(\gamma S^n\tau + \delta )
\right)^r=\left(-i(c\tau + d ) \right)^r$, we have
\begin{eqnarray}
\lefteqn{F_\nu(\tau)-\left(%
\begin{array}{ccc}
  e^{-2 \pi i n m_1} &   &   \\
   & \ddots &   \\
    &   & e^{-2 \pi i n m_p} \\
\end{array}%
\right)p_{V,\nu}(S^n\tau,\varepsilon,\rho)}\\
&&=\varepsilon^{-1}(V)\left(-i(c\tau + d ) \right)^r\left(%
\begin{array}{ccc}
  e^{-2 \pi i n m_1} &   &   \\
   & \ddots &   \\
    &   & e^{-2 \pi i n m_p} \\
\end{array}%
\right)\\
&&\rho^{-1}(V)\left(%
\begin{array}{ccc}
  e^{-2 \pi i k m_1} &   &   \\
   & \ddots &   \\
    &   & e^{-2 \pi i k m_p} \\
\end{array}%
\right)F_\nu(M\tau)\\
&&=\varepsilon^{-1}(M)\rho^{-1}(M)\left(-i(c\tau + d )
\right)^rF_\nu(M\tau)
\end{eqnarray}
and since
\begin{equation}
\left(%
\begin{array}{ccc}
  e^{-2 \pi i n m_1} &   &   \\
   & \ddots &   \\
    &   & e^{-2 \pi i n m_p} \\
\end{array}%
\right)p_{V,\nu}(S^n\tau,\varepsilon,\rho)
\end{equation}
is a column vector of degree at most $r$ the proof is complete
\end{proof}
\begin{equation}
\end{equation}
\begin{eqnarray}
\lefteqn{}
\end{eqnarray}

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\end{document}
